Indianapolis topographic map
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Indianapolis
Indianapolis is located within a physiographic province known as the Tipton Till Plain, a flat, gently rolling terrain underlain by glacial deposits known as till. The lowest point in the city is about 650 feet (198 m) above mean sea level, with the highest natural elevation at about 900 feet (274 m) above sea level. Few hills or short ridges, known as kames, rise about 100 feet (30 m) to 130 feet (40 m) above the surrounding terrain. The city lies just north of the Indiana Uplands, a region characterized by rolling hills and high limestone content.
About this map
Name: Indianapolis topographic map, elevation, terrain.
Location: Indianapolis, Marion County, Indiana, United States (39.63216 -86.32812 39.92753 -85.93804)
Average elevation: 791 ft
Minimum elevation: 643 ft
Maximum elevation: 928 ft
Marion County trails, hiking, mountain biking, running and outdoor activities
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The city's elevation, measured in feet above sea level, ranges from 766 (the Beech Creek waterway, where it is crossed by South 9th Avenue) to 845 (the northeastern portion of the Amtrak railroad property). It is higher than that of downtown Indianapolis.
Average elevation: 810 ft